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Тема 9. Растворы электролитов
(продолжение)
в-т
«а»
«б»
31 HNO
3
; NH
4
NO
3
Cd
2+
+ 2 OH ‾ = Cd(OH)
2
32 H
2
CO
3
; CaOHCl
CO
3
2
‾ + Ba
2+
= BaCO
3
33 HCl; HCN
Ca
2+
+ C
2
O
4
2
‾
= CaC
2
O
4
34 H
2
SO
3
; AgNO
3
Sr
2+
+ SO
4
2
‾ = SrSO
4
35 H
3
PO
4
; KCN
Cu
2+
+ 4 Br ‾ = [CuBr
4
]
2
‾
36 HNO
3
; KHCO
3
Pb
2+
+ SO
4
2
‾ = PbSO
4
37 H
2
S; Sr(OH)
2
Ba
2+
+ SO
4
2
‾ = BaSO
4
38 HF; K
2
HPO
4
AgBr
+ Br ‾ = [AgBr
2
] ‾
39 HCN; RbOH
H
+
+ OH ‾ = HOH
40 Н
2
CO
3
; NiOHNO
3
NH
4
+
+ OH ‾ = NH
3
+ H
2
O
41 H
2
S; Na
3
PO
4
PbI
2
+ 2 I ‾ = [PbI
4
]
2
‾
42 HBr; KHSO
3
Fe
3+
+ 6 F ‾ = [FeF
6
]
3
‾
43 CuOHBr; KNO
2
Al
3+
+ 6 F ‾ = [AlF
6
]
3
‾
44 Mg(HSO
4
)
2
; HBrO
Zn
2+
+ 4 OH ‾ = [Zn(OH)
4
]
2
‾
45 HIO; Na
2
S
Al
3+
+ 6 OH ‾ = [Аl(OH)
6
]
3
‾
46 K
2
SO
3
; NaHS
Ba
2+
+ CrO
4
2
‾ = BaCrO
4
47 KI; (NH
4
)
2
SO
4
2 Ag
+
+ SO
4
2
‾ = Ag
2
SO
4
48 KНCO
3
; KCl
Pb
2+
+ 2 OH ‾ = Pb(OH)
2
49 FeSO
4
; HF
3 Mn
2+
+ 2 PO
4
3
‾ = Mn
3
(PO
4
)
2
50 KNO
3
; HCN
Fe
3+
+ 3 OH ‾ = Fe(OH)
3
51 KHCO
3
; HCN
Mn
2+
+ 2 OH‾ = Mn(OH)
2
52 H
2
CO
3
; K
2
HPO
4
Cr(OH)
3
+ 3 OH ‾ = [Cr(OH)
6
]
3
‾
53 BaCl
2
; H
2
S
Fe
3+
+ 6 CN ‾ = [Fe(CN)
6
]
3
‾
54 Sr(OH)
2
; FeCl
3
2 H
+
+ SiO
3
2
‾ = H
2
SiO
3
55 H
2
S; K
2
SiO
3
2 H
+
+ SO
3
2
‾ = SO
2
+ H
2
O
56 HNO
3
; KHCO
3
Pb
2+
+ SO
4
2
‾ = PbSO
4
57 H
2
S; Sr(OH)
2
Be
2+
+ SO
4
2
‾ = BeSO
4
58 HF; CrOH(NO
3
)
2
Ag
+
+ Br ‾ = AgBr
59 Cu(HSO
4
)
2
; RbOH
H
+
+ OH ‾ = HOH
60 Н
2
CO
3
; NiOHBr
NH
4
+
+ OH ‾ = NH
3
+ H
2
O